Identify the Sprint ID in Jira Software Data Center
Platform Notice: Data Center Only - This article only applies to Atlassian products on the Data Center platform.
Note that this KB was created for the Data Center version of the product. Data Center KBs for non-Data-Center-specific features may also work for Server versions of the product, however they have not been tested. Support for Server* products ended on February 15th 2024. If you are running a Server product, you can visit the Atlassian Server end of support announcement to review your migration options.
*Except Fisheye and Crucible
Summary
Sprint ID numbers can be retrieved from the Jira User Interface (UI) in several ways. They are useful when performing bulk import/export tasks, actions via the REST API, and SQL queries on Jira DB.
This article applies to Jira Data Center. If you are on Jira Cloud, please checkout Identify the Sprint ID in Jira Cloud
Solution
Retrieve sprint ID from Jira issue view
Open an issue, that is assigned to the sprint
Place your cursor over the sprint name in the Sprint field. The sprint ID will show up in the browser's status bar.

The sprint ID is the numerical value at the end of the string following "sprintId="
Retrieve sprint ID from JQL search auto-complete
Start searching for the Sprint by its name using JQL Advanced Search. As you enter the sprint name, JQL will provide a dropdown with sprints that match your entered characters. Clicking on one of these options will convert the sprint name to ID in the JQL search bar.
Query sprint ID value from Jira Database via SQL
Access the Jira database to query the AO_60DB71_SPRINT table and find Sprint ID values. You can also retrieve the sprint's associated board and filter.
PostgreSQL
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SELECT sp."id" AS sprintID,
sp."name" AS sprintName,
rv."name" AS boardName,
rv."id" AS boardID,
sr.filtername_lower AS filterName,
sr.reqcontent AS filter,
sr.id AS filterID
FROM searchrequest AS sr
JOIN "ao_60db71_rapidview" rv
ON sr.id = rv."saved_filter_id"
JOIN "ao_60db71_sprint" sp
ON sp."rapid_view_id" = rv."id"
ORDER BY sp."NAME";
For example:
PostgreSQL
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jira9121=# SELECT sp."ID" as sprintID, sp."NAME" as sprintName, rv."NAME" as boardName, rv."ID" as boardID, sr.filtername_lower as filterName, sr.reqcontent as filter, sr.ID as filterID FROM searchrequest as sr JOIN "AO_60DB71_RAPIDVIEW" rv ON sr.ID = rv."SAVED_FILTER_ID" JOIN "AO_60DB71_SPRINT" sp on sp."RAPID_VIEW_ID" = rv."ID" ORDER BY sp."NAME";
sprintid | sprintname | boardname | boardid | filtername | filter | filterid
----------+-------------------------+-----------+---------+----------------------+---------------------------------+----------
6 | Sample Sprint 1 | ES board | 3 | filter for es board | project = ES ORDER BY Rank ASC | 10200
4 | Sample Sprint 1 | SP2 board | 2 | filter for sp2 board | project = SP2 ORDER BY Rank ASC | 10100
2 | Sample Sprint 1 | SP board | 1 | filter for sp board | project = SP ORDER BY key desc | 10000
In the above example, we see three sprints with the same name, 'Sample Sprint 1'. Even though the sprints can share the same name, they must be assigned unique ID numbers. They also belong to three different project boards, which can help us select the correct sprint ID for the correct project.
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